Question

for a sequence (tn) if Sn = n²(n+1) then find the first three terms of (tn)

Answer 1

Hey frnd.....

Thanks for asking this question.
Here is your answer....

✨Arthimetic Progression ✨


The solution is in the attachment.


Hope this would help you.

Answer 2

Answer:

Required three terms are 2 , 10 , 24

Step-by-step explanation:

Given : $S_n=n^2(n+1)$ of the sequence (tn).

To find : The first three terms of (tn)

Solution :

We know, $S_n=n^2(n+1)$

Now, put n=1,2,3 to get the sum

n=1

$S_1=1^2(1+1)$

$S_1=2$

n=2

$S_2=2^2(2+1)$

$S_2=12$

n=3

$S_3=3^2(3+1)$

$S_3=36$

In the sequence first term is

$t_1=s_1=2$

Second term is

$t_2=S_2-S_1=12-2=10$

Third term is

$t_3=S_3-S_2=36-12=24$

Required three terms are 2 , 10 , 24