for a sequence {tn}If sn =n2(n+1) then find the first three term of {tn}.
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sn =n^2(n+1)
s1=1^2(1+1)=1*2=2
s2=2^2(2+1)=4*3=12
s3=3^2(3+1)=9*4=36
s4=4^2(4+1)=16*5=80
t1=s1=2
t2=s2-s1=12-2=10
t3=s3-s2=36-12=24
therefore
first three terms are
2,10,24
s1=1^2(1+1)=1*2=2
s2=2^2(2+1)=4*3=12
s3=3^2(3+1)=9*4=36
s4=4^2(4+1)=16*5=80
t1=s1=2
t2=s2-s1=12-2=10
t3=s3-s2=36-12=24
therefore
first three terms are
2,10,24
ur welcome
or one question
if the term(a) and the common differance (d) of a certain Arithmetic prograssion(A.P.) is 4 and o respectively. find the first four term of that of that A.P.
solve the question
a=4,d=0 here common difference =0
then first three terms are 4,4,4
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