Question

For a single slit of width 'a' the first diffraction maximaum with light of wavelenghth used 5000
A.U. is a
a) 2/2a b) a la c) 1.5 2/a d) 22/a
plz answer the question it's urgent...​

Answer 1

Answer:

Condition for obtaining m

th

order minima is

asinθ=mλ

Thus for obtaining first diffraction minima,

asinθ=λ

⟹a=

sinθ

λ

=

1/2

5000×10

−10

m

=10×10

−5

cm