For a species having logistic growth, if K = 20,000 and r = 0.15, the maximum sustainable yield will be
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.dN/dt=r .N N=number of individuals
r=growth rate
K is given 20,000
N=k/2=20,000/2=10,000
so, 0.15*10,000=1500
r=growth rate
K is given 20,000
N=k/2=20,000/2=10,000
so, 0.15*10,000=1500
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