For a spherical mirror show that r=2f.
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Hi,
Here is the answer to your query:-
Consider a ray of light AB, parallel to the principal axis, incident on a spherical mirror at point B. The normal to the surface at point B is CB and CP = CB = R, is the radius of curvature. The ray AB, after reflection from mirror will pass through F (concave mirror) or will appear to diverge from F (convex mirror) and obeys law of reflection, i.e., i = r.
From the geometry of the figure,
If the aperture of the mirror is small, B lies close to P, BF = PF
or FC = FP = PF
or PC = PF + FC = PF + PF
or R = 2 PF = 2f
or f=R/2
or 2f=R
or R=2f
Thanks
@SHIVAM
Here is the answer to your query:-
Consider a ray of light AB, parallel to the principal axis, incident on a spherical mirror at point B. The normal to the surface at point B is CB and CP = CB = R, is the radius of curvature. The ray AB, after reflection from mirror will pass through F (concave mirror) or will appear to diverge from F (convex mirror) and obeys law of reflection, i.e., i = r.
From the geometry of the figure,
If the aperture of the mirror is small, B lies close to P, BF = PF
or FC = FP = PF
or PC = PF + FC = PF + PF
or R = 2 PF = 2f
or f=R/2
or 2f=R
or R=2f
Thanks
@SHIVAM
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