Question

for a substance,the magnetic susceptibility at 25°C is -0.00021. the magnetic susceptibility at 35°C is - a)-0.0023 b)-0.00021 c)0.212 d)0.00041​

Answer 1

Given:

temperature T₁ =  25°C

magnetic susceptibility X₁ = - 0.00021

temperature T₂ = 35°C

To find:

magnetic susceptibility at 35°C X₂ =?

Step-to-step-explanation:

• According to curie's law, the magnetic susceptibility is given by

        $\displaystyle X =\frac{C}{T}$

        where

        X = magnetic susceptibility

        C = speed of light

        T = temperature

• The speed of light is always constant.
• According to the above equation, magnetic susceptibility is inversely proportional to the temperature.

        X ∝ $\displaystyle \frac{1}{T}$

    ∴  $\displaystyle \frac{X_1}{X_2} = \frac{T_2}{T_1}$

• Put the given values in the above equation to find the magnetic susceptibility at 35°C.

        $\displaystyle \frac{-0.00021}{X_2} =\frac{35}{25}$

        X₂ = - 0.00015

• Hence, the magnetic susceptibility at 35°C is - 0.00015.