Question

For a transistor the current amplification factor is 0.8 the transistor is connected to common emitter configuration the change in the collector current when base current changes by 6 milliampere

Answer 1

Hey Dear,

● Answer -

∆Ic = 24 mA

● Explaination -

# Given -

α = 0.8

∆Ib = 6 mA

# Solution -

For a transistor, α and β are related as -

β = α / (1-α)

β = 0.8 / (1-0.8)

β = 4

But, current gain is calculated by formula -

β = ∆Ic / ∆Ib

∆Ic = β × ∆Ib

∆Ic = 4 × 6

∆Ic = 24 mA

Therefore, collector current changes by 24 mA.

Hope this was useful..