Question

For a zero order reaction 2A-P t1/2=120s and its initial concentration is 2M.Calculate its rate constant​

Answer 1

Answer:

It is a Zero Order Reaction

k=

t

[A

0

]−[A]

2×10

−2

=

25

[A

0

]−[0.5]

[A

0

]=1 M

Answer 2

Answer:

1/240 mol/l/s

Explanation:

for zero order reaction

rate constant = rate of rxn ------ eqn 1

now , rate of rxn = -1/2 [(0 -2) mol/l]/t

t = time taken to complete full rxn

t = t1/2 × 2

t = 120s × 2 = 240s

rate of rxn = -1/2[(0-2)mol/l]/240s

= 1/240mol/l/s

so rate constant k = 1/240mol/l/s by eqn 1