For all sets A and B, show that (A union B) - B =A - B
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Step-by-step explanation:
“The stuff in A is the same as the stuff either: 1.) in A but not B or 2.) in both A and B.” Read this way, what you want to show is pretty clear, but perhaps you would like something more proof-y.
Consider the following (I’m using ∨ for “or” and ∧ for “and”):
(A−B)∪(A∩B)={x∣x∈A∧x∉B}∪{x∣x∈A∧x∈B} (Definition of set difference, intersection)
={x∣(x∈A∧x∉B)∨(x∈A∧x∈B)} (Definition of union)
={x∣x∈A∧(x∈B∨x∉B)} (Distributivity of ∧ over ∨ )
={x∣x∈A}=A
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