for an A.P 5,11,17,23,.....the value of the tenth (t10)is....
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Step-by-step explanation:
a=5 and d=6
tn=a+(n-1)d
t10= 5+(10-1)×6
=5+9×6
=5+54
t10=59
therefore the value of the tenth term of AP is 59
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