Question

For an A. P. 6,4,2,....,
${s}^{10}$
plz...!!
help me mates...!

Answer 1

Answer:

Step-by-step explanation:

a=6

a2=4 d=a2-a1=4-6=-4

s10=10/2[2*6-9[2]]

    =5[12-18]

     =5*-6

     =-30

Answer 2

First term is 6

Common difference is 4-6=-2

Then,

Sum=n/2(2a+(n-1)d)

S10 = 10/2 (2×6 + (10-1) × -2)

=>sum=5 (12 +( -18))

=> sum= 5 × -6= -30 Ans