Question

for an A.P. If a=100, d=100 what is t10​

Answer 1

Answer:

$\star\:\: \large \boxed{t_{10} = 1000}\:\:\star$

Step-by-step explanation:

→ Given that :–

• a=100
• d=100

→ To Find :–

• $t_{10} \: (10th \: term \: of \: the \: following \: a.p.)$

→ Formula Used :–

$a_n = a + (n - 1)d \: where \: you \: can \: also \: say \: a_n = t_n$

→ You need to remember these formulas also :

• $s_n = \frac{n}{2} [2a + (n - 1) \times d]$
• $s_n = \frac{n}{2} [a + l] \: where \: l \: is \: last \: term$

→ Solution :–

We will use this formula:

$a_n = a + (n - 1)d \: where \: a = 100,d = 100 \: and \: n = 10.$

$\implies a_{10} = 100 + (10 - 1) \times 100$

$\implies a_{10} = 100 +( 9 \times 100)$

$\implies a_{10} = 100 +900$

$\implies \boxed{a_{10} = 1000}$

Therefore, 10th Term of this A.P. is 1000.

→ What Do you need to Know about A.P.(Arithmetic Progression):

Arithmetic Progression is a series of number which have a common difference after every number of that series.

→ How to find that any series in Arithmetic Progression:

If we need to know that this is a Arithmetic Progression then it should have a common difference as I have mentioned it in the definition.

Answer 2

Step-by-step explanation:

Answer:

\star\:\: \large \boxed{t_{10} = 1000}\:\:\star⋆

t

10

=1000

⋆

Step-by-step explanation:

→ Given that :–

a=100

d=100

→ To Find :–

t_{10} \: (10th \: term \: of \: the \: following \: a.p.)t

10

(10thtermofthefollowinga.p.)

→ Formula Used :–

a_n = a + (n - 1)d \: where \: you \: can \: also \: say \: a_n = t_na

n

=a+(n−1)dwhereyoucanalsosaya

n

=t

n

→ You need to remember these formulas also :

s_n = \frac{n}{2} [2a + (n - 1) \times d]s

n

=

2

n

[2a+(n−1)×d]

s_n = \frac{n}{2} [a + l] \: where \: l \: is \: last \: terms

n

=

2

n

[a+l]wherelislastterm

→ Solution :–

We will use this formula:

a_n = a + (n - 1)d \: where \: a = 100,d = 100 \: and \: n = 10.a

n

=a+(n−1)dwherea=100,d=100andn=10.

\implies a_{10} = 100 + (10 - 1) \times 100⟹a

10

=100+(10−1)×100

\implies a_{10} = 100 +( 9 \times 100)⟹a

10

=100+(9×100)

\implies a_{10} = 100 +900⟹a

10

=100+900

\implies \boxed{a_{10} = 1000}⟹

a

10

=1000

Therefore, 10th Term of this A.P. is 1000.

→ What Do you need to Know about A.P.(Arithmetic Progression):