Question

For an A.P., if a = 8 and d = 8 then Sn = ?​

Answer 1

Answer:

Here a=8 d=8 first we have to find tn.

Here a=8 d=8 first we have to find tn.tn= a+(n-1) d

Here a=8 d=8 first we have to find tn.tn= a+(n-1) d= 8+(n-1) 8

Here a=8 d=8 first we have to find tn.tn= a+(n-1) d= 8+(n-1) 8= 8+(8n-1)

Here a=8 d=8 first we have to find tn.tn= a+(n-1) d= 8+(n-1) 8= 8+(8n-1)= 8n=0

Here a=8 d=8 first we have to find tn.tn= a+(n-1) d= 8+(n-1) 8= 8+(8n-1)= 8n=0n= 0/8

Here a=8 d=8 first we have to find tn.tn= a+(n-1) d= 8+(n-1) 8= 8+(8n-1)= 8n=0n= 0/8n= 0.

Here a=8 d=8 first we have to find tn.tn= a+(n-1) d= 8+(n-1) 8= 8+(8n-1)= 8n=0n= 0/8n= 0.Now ,

Here a=8 d=8 first we have to find tn.tn= a+(n-1) d= 8+(n-1) 8= 8+(8n-1)= 8n=0n= 0/8n= 0.Now ,Sn = n/2 {2a ( n-1) d}

Here a=8 d=8 first we have to find tn.tn= a+(n-1) d= 8+(n-1) 8= 8+(8n-1)= 8n=0n= 0/8n= 0.Now ,Sn = n/2 {2a ( n-1) d}Sn = 0/2 {2*8(0-1) 8}

Here a=8 d=8 first we have to find tn.tn= a+(n-1) d= 8+(n-1) 8= 8+(8n-1)= 8n=0n= 0/8n= 0.Now ,Sn = n/2 {2a ( n-1) d}Sn = 0/2 {2*8(0-1) 8}Sn = 0 { 16 -1 *8 }

Here a=8 d=8 first we have to find tn.tn= a+(n-1) d= 8+(n-1) 8= 8+(8n-1)= 8n=0n= 0/8n= 0.Now ,Sn = n/2 {2a ( n-1) d}Sn = 0/2 {2*8(0-1) 8}Sn = 0 { 16 -1 *8 }Sn = 24.

Step-by-step explanation:

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Answer 2

Answer:

An=24

n=3

Sn=6

Step-by-step explanation:

An=a+2d

An=8+2(8)

An=16+8

An=24

An=a+(n+1)d

24=8+(n-1)8

24=8+8n-8

24=8n

n=24/8

n=3

Sn=n(n+1/2)

Sn=3(3+1/2)

Sn=3×4/2

Sn=3×2

Sn=6