for an A.p,ifa=3,d=5 ehatvis the value of eleventh term
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Step-by-step explanation:
First term, a
1
=−3
difference, d=a
2
−a
1
=1−(−3)=4
we know that, a
n
=a+(n−1)d
a
11
=−3+(11−1)4
=−3+(10)4
=−3+40
a
11
=37
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