Question

for an A.P., t3 =13 and t7 = 9. What is the value of t5?​

Answer 1

Answer:

11

Step-by-step explanation:

common difference = diff. in terms ÷ diff. in position

$(9 - 13) \div (7 - 3)$

$(- 4 )\div 4 = - 1$

$t5 = t3 \: - 2$

$t5 = 13 - 2 = 11$

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