Question

for an ap a=0 d= -3 find s12​

Answer 1

Answer:

An= a+(n-1)d

so,

0+(12-1)×-3

=11×-3

= -33

Sn= n/2[a+l]

=6×-33

= -198

Step-by-step explanation:

hope this will help you

Answer 2

Answer:

S12=-198

Step-by-step explanation:

= Sn = n/2(2a+(n-1)d

= n=12

= a=0

= d= -3

= S12 = 12/2((2×0)+(12-1)-3)

= S12 = 6(11×[-3])

= S12 = 6×(-33)

= S12 = -198

I hope it helped...

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