Question

for an ap a is 6 and d is 3 find s 27​

Answer 1

$\huge\bold\green{ solution }$

$tn = a + (n - 1)d \\ \\ t27 = 6 + (27 - 1)3 \\ \\ t27 = 6 + (71 - 3) \\ \\ t27 = 6 + (68) \\ \\ t27 = 74$

hence T27 = 74 of an AP