For an AP(arithmetic progression) if S49=100 and T50=25 then S50=____
Answers
Answered by
5
now
t50=25
a+49d=25
a=25-49d_ _ _ _ _ 1
now,
s49=100
49/2[ 2(25-49d) + 48d]= 100
49[50-98d+48d]=200
2450-2450d
d=45/49
now putting this value in 1
a= 25 - 45
a= -20
now
s50= 50/2[-40+45]
s50=125 - - - - - - -ans
t50=25
a+49d=25
a=25-49d_ _ _ _ _ 1
now,
s49=100
49/2[ 2(25-49d) + 48d]= 100
49[50-98d+48d]=200
2450-2450d
d=45/49
now putting this value in 1
a= 25 - 45
a= -20
now
s50= 50/2[-40+45]
s50=125 - - - - - - -ans
Answered by
3
sum of 50 terms in arithmetic progression is 125
Similar questions