Math, asked by prituldave, 1 year ago

Line PA and line PB are two tangents drawn from a common exterior point circle(o,r) . a third tangent line CD is drawn such that it touches the
circle(o,r) at Q and A-C-p and B-d-p Ap=8.5 ,dq=3.5,dp=_____


dewanaaryan1: can you click a picture and send

Answers

Answered by pranavchoudhary
1
dp will be equal to pb + bd 

now pb = 8.5 and bd = 3.5

therefor pb= 8.5+3.5=12 

ans=12
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