For an ap the 1st term and last term is 13 and 216 common difference is 7 how many termas are there in ap find m of all terms
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Answer:
n = 30
Step-by-step explanation:
a = 13, d = 7 last term = 216
an = a + (n-1)d
216 = 13 + (n-1)7
216 - 13 = (n-1)7
203 = (n-1)7
n - 1 = 203/7
n - 1 = 29
n = 29 + 1
n = 30
therefore there are 30 terms in the AP
sum of all the terms
Sn = n/2 (a + l)
= 30/2 (13 + 216)
= 15 × 229
= 3435
hope you get your answer
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