for an arithmatic progression a=1 and d=4 what is the value of r if tn=81
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Answer:
The answer will be 21.
Step-by-step explanation:
We have given;
a = 1;
d = 4;
tn = 81;
For this the formula we apply will be;
an(tn) = a + d (n - 1);
Hence, we put the values in their respective variables of the formula;
81 = 1 + (4)(n - 1);
80 = 4n - 4;
84 = 4n;
n = 21;
Hence, the value of n (no. of terms) = 21.
That's all.
tarun9788:
thankyou
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