Question

For an arithmetic progression t1 = 2, tn = 41 and Sn = 860, what is the value of n?
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Answer 1

Answer:

n = 40

Step-by-step explanation:

1. Sn = n/2×(t+tn)

2. Sn = n/2×(2t+(t-1)d)

both of f these are formula of Sn

but in this question you must use the 1st one

Hope it will help you

Answer 2

Answer:

Answer:

n = 40

Step-by-step explanation:

1. Sn = n/2×(t+tn)

2. Sn = n/2×(2t+(t-1)d)

both of f these are formula of Sn

but in this question you must use the 1st on

Step-by-step explanation:

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