Question

for an arithmetic progression , T7=18,T18=7 ,find T101​

Answer 1

Step-by-step explanation:

Insta dedo usme btadunga..

Answer 2

Answer:

let the first term be a and common difference be d

then

a+6d = 18.......(1)

a+17d = 7 ......(2)

by subtract equation 2 from 1

(a+17d) -(a+6d) = 7-18

a+17d - a-6d = -11

11d = -11

d = -1

put the value of d in equation 1

we get

a+6(-1)=18

a-6=18

a= 18+6

a= 24

now

t101= a +100d

= 24+100(-1)

= 24-100

= -76