Question

For an emission of wavelength 5000 Angstrom, at what temperatures both spontaneous and stimulated emissions will be same?

Answer 1

For an emission of wavelength 5000 Angstrom, both spontaneous and stimulated emissions will be same at temperature 28869.6 K

The Temperature is calculated by the formula

$\frac{N}{n}$=e^(-hc/λKT)-1

here, n is number of spontaneous emission, N number of stimulated emission, h is Planck's constant,  c is speed of light, K is Boltzmann constant, and T is temperature

Plugging the values in the above equation

1=e^((-6.64*10^(-34)*3*10^8)/(5000*10^(-10)*1.38*(10^-23)*T)

T=28869.6 K