Question

for an equilibrium A+B = C+D ,Kc =60 ; starting with 7 moles of A, 8 moles of B and 14 moles of D , how many miles of C would be present at equilibrium...​

Answer 1

Hope this helps!

Not sure about this one...

Answer 2

Moles of C would be present at equilibrium are 6.5

Explanation :

Equilibrium constant is the ratio of the concentration of products to the concentration of reactants each term raised to its stochiometric coefficients.

The balanced chemical reaction is:

         $A+B\rightleftharpoons C+D$                                

Initial amount     7     8               0      14  

At eqm.             (7-x)   (8-x)         x     (14+x)

As we are given that:

$K_c=\frac{[C]\times [D]}{[A]\times [B]}$

$60=\frac{(14-x)\times x}{(7-x)\times (8-x)}$

$x=6.5$

Amount of C at equilibrium = 6.5 moles

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