Question

IN ALGEBRAIC IDENTITES
WRITE 15 FORMULAS​

Answer 1

Step-by-step explanation:

. (a + b)2 = a2 + 2ab + b2

. (a – b)2 = a2 – 2ab + b2

. a2 – b2 = (a + b)(a – b)

. (x + a)(x + b) = x2 + (a + b) x + ab

. (a + b + c)2 = a2 + b2 + c2 + 2ab + 2bc + 2ca

. (a + b)3 = a3 + b3 + 3ab (a + b)

. (a – b)3 = a3 – b3 – 3ab (a – b)

. a3 + b3 + c3– 3abc = (a + b + c)(a2 + b2 + c2 – ab – bc – ca)

. (x – y) (x – z) = x2 – (y + z) x + yz

. (a + b + c)2 = a2 + b2 + c2 + 2 · a · b + 2 · a · c + 2 · b · c

Answer 2

$\huge{\boxed{\boxed{\red{\ulcorner{\mid{\overline{\underline{\bf{@nswer..}}}}}\mid}}}}$

• (a + b)2 = a2 + 2ab + b2
• (a – b)2 = a2 – 2ab + b2
• a2 – b2 = (a + b)(a – b)
• (x + a)(x + b) = x2 + (a + b) x + ab
• (a + b + c)2 = a2 + b2 + c2 + 2ab + 2bc + 2ca
• (a + b)3 = a3 + b3 + 3ab (a + b)
• (a – b)3 = a3 – b3 – 3ab (a – b)
• a3 + b3 + c3– 3abc = (a + b + c)(a2 + b2 + c2 – ab – bc – ca)