Physics, asked by waniArora, 1 year ago

for an isobaric process the ratio of amount of heat supplied to the work done by the gas for diatomic gas will be​

Answers

Answered by nalinsingh
14

Hey !

In an isobaric process, heat supplied to the system,

                   dQ = nCpdt

And work done by the system,

                   dW = nRdT

Also, specific heat for diatomic gas at constant pressure,

                    Cp = 7/2 R

Therefore ratio of heat supplied to the system and work done by the system

         (dQ/dW) = nCpdT/nRdT = Cp/R

      =  7R/2 / R = 7/2

(or)       dQ : dW = 7:2

Good luck !


piyushssngh: Awesome.
Answered by varshika1664
0

Answer:

The Correct answer would be 7 : 2. The ratio of amount of heat supplied to the work done by a diatomic gas in an isobaric process would be 7 : 2.

Explanation:

  • Heat is basically a form of energy. It usually transfers from one body at a higher temperature to the other body which is basically at the lower temperature.
  • Work done is basically the energy interaction by a system with its surroundings. More precisely, work done is the energy transfer which is associated with the force acting through a distance on a particular body.
  • An Isobaric process is the one which occurs at a constant pressure throughout the whole process. There is change in temperature, but not in the pressure.

Basically, after all the calculations and observations, it was found out that ratio of heat to work done for a diatomic gas in an isobaric process is 7:2.

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