Question

For an object kept at a distance of 36cm from a concave mirror of focal length 12cm,what is the nature of the object? best answer will get Brainliest please answer.....

Answer 1

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${\bold{\underline{Given-}}}$

u=-36cm

f=-12cm [ focal length of concave is always negative ]

$\frac{1}{f} = \frac{1}{v} + \frac{1}{u} \\ \\ \frac{1}{ - 12} = \frac{1}{v} + \frac{1}{ - 36} \\ \frac{1}{v} = \frac{1}{ - 12} - \frac{1}{ - 36} \\ \\ \frac{1}{v} = \frac{3 - 1}{ - 36} \\ \frac{1}{v} = \frac{2}{ - 36} \\ \\ \\ \\ v = - 18cm$

since v = -18cm

Nature is real and inverted.

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