Question

For an object projected from ground with speed u horizontal range is 2 times its maximum height attained by it .horizontal range of object is

Answer 1

Maximum height for a projectile motion :

H max = u²Sin²Ф / 2g

u = initial velocity of the projection

Ф = Angle of projection at initial velocity

g = acceleration due to gravity.

According goto the question, the range is double the height.

Range = 2{u² Sin²Ф / 2g}

= u²Sin²Ф / g
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