Question

For an organ pipie closed at one end of lenght 2 m, velocity 320 what is the resonating frequency

Answer 1

The 1st harmonic would occur at lambda / 4

since the closed end is a node and the open end an anti-node.

Thus, the wavelength lambda = 8 m

f = velocity / wavelenght = 320 m/s / 8 m = 40 / s