Question

For any acute angle θ,prove that
i) sin^2θ+cos^2θ=1
ii)1+tan^2θ=sec^2θ
iii)1+cot^2θ=cosec^2θ

Answer 1

Answer:

Step-by-step explanation:

Here is the full explanation-----

Answer 2

Step-by-step explanation:

• sin^2@+cos^2@

=(opp side)^2/(hypo)^2+(adj side)^2/(hypo)^2

=*hypo)^2/(hypo)^2

=1

• 1+tan^2@

=1+(opp side)^2/(adj side)^2

=(hypo)^2/*adj side)^2

=sec^2@

• 1+cot^2@

=1+(adj side)^2/(opp side)^2.

=(hypo)^2/(opp side)^2

=cosec^2@