Question

Three resistors of 6 ohm each are connected in parallel. Three such combinations are then connected in series to a 3 v battery find the current flowing through each resistors

Answer 1

Answer:

Explanation:Given

V=3v

R=6ohm

R/s=R1+R2+R3

=6+6+6

18 ohm

I=?

V=I/R

5=I/18

I=5*18

=90 A

Answer 2

Answer:

1/6

Explanation:

V = 3v

RS = R1 + R2 + R3

R = 6 + 6 + 6

R = 18

V = IR

I = V/R

I = 3/18

I = 1/6