For any integer a and 3 there exist unique integers q and r such that a=3q+r. find the possible value of r
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Answered by
2
HERES YOUR ANSWER
since the lemma say that..
p(x)=g(x)×q(x)+r(x)
here 0=< r<b
so if b= 3
the possible value if r are 0,1,2
HOPE IT HELPS!!
Answered by
2
Answer:
Heres your answer
By Euclid devision lemma
p(x) = g(x) × q(x) + r(x)
Where 0<=r<b
So b= 3
And the possible values of r is 0,1,2
Hope it helps ✌
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