For any positive integer n, prove that n3 – n is divisible by 6.
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n = 2q or 2q + 1, where q is some integer. Then n is divisible by 2. n+1= 2 (q + 1) is divisible by 2. ... n3 – n = n (n – 1) (n + 1) is divisible by 6.
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