Math, asked by sarthakbhatia98, 8 months ago

For any positive real number X , prove that there exits an irrational number Y such that 0<Y<X

Answers

Answered by pramalanmidhila

Step-by-step explanation:

If x is irrational then y = x/2 is also an irrational number such that 0 < y < xIf x is rational then y = x/√2 is an irrational number such thatHence for any positive real number x there exists an irrational number y such that 0 < y < x.

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