Question

for any triangle abc, show that , tan B+C/2= cot A/2​

Answer 1

Step-by-step explanation:

We know that for triangle ABC

A+B+C=180°

B+C=180°-A

B+C/2=90°-A/2

tan(B+C/2)= tan(90°- A/2)

tan(B+C/2)= cot A/2