Question

For Complex Number, Find the argument of i^3.​

Answer 1

Answer:

Solving

$i {}^{3} =( i {}^{2} )i = ( - 1)i = - i$

note i^2=-1

ARGUMENT IS

$a + bi = 0 + ( - 1)i$

$r \cos( - ) = 0 \\ r \sin( - ) = - 1$

$r {}^{2} ( \cos {}^{2} + \sin {}^{2}) = \: (0) {}^{2} + ( - 1) {}^{2} \\ = 1$