hi
solve these...
I will be thankful
solve 13. 14. 15. 12.
any two
13 is compulsary
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let b is breadth of rectangle then length is b+18
so by given conditions
let area A of rectangle so
b+16 be the new breadth and b+18+6 is length so
area is A+168
so
b(b+18)=A
and
(b+6)(b+18+6)=A+168
so
b(b+18)+6b+6(b+18)+6b=A+168
so
A+18b+18*6=A+168
18b=168-108
b=5
Hope it helps you
Dear!
so by given conditions
let area A of rectangle so
b+16 be the new breadth and b+18+6 is length so
area is A+168
so
b(b+18)=A
and
(b+6)(b+18+6)=A+168
so
b(b+18)+6b+6(b+18)+6b=A+168
so
A+18b+18*6=A+168
18b=168-108
b=5
Hope it helps you
Dear!
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1
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