Question

for data given below:
marks obtained. below 10 below 20 below 30 below 40 below 50
No. of students. 5 16 28 42 72
if x is class mark of modal class and y is the upper limit of the median class then the value of 2x+y is
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Answer 1

Solution :-

Marks obtained No. of students. CF

0 - 10 5 5

10 - 20 11 16

20 - 30 12 28

30 - 40 14 42

40 - 50 30 72

Now, we know that,

• The modal class is the class with the highest frequency.
• The median class interval is the corresponding class where the median value falls.
• Class marks of modal class = (Lower limit of modal class + higher limit of modal class) / 2 .

So,

from given data we have :-

• Modal class :- Highest frequency as 30 = 40 - 50
• class marks of modal class = (40 + 50)/2 = 90/2 = 45 = x .
• Median of No. of students = (5 + 1)/2 = 3rd term in ascending order = 12 .
• Median class = containing median = 30 - 40 .
• upper limit of median class = 40 = y .

Therefore,

→ 2x + y

→ 2 * 45 + 40

→ 90 + 40

→ 130 (Ans.)

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Answer 2

Answer:

Step-by-step explanation: