Chemistry, asked by singhhardeepsingh807, 10 months ago

For dilute solution Raoult’s law states that *

2 points



Relative lowering of vapour pressure of dilute solution is equal to the mole fraction of the solvent

Vapour pressure of the solution is equal to the vapour pressure of the solvent

Relative lowering of vapour pressure of a dilute solution is equal to the mole fraction of the solute

Lowering of vapour pressure is equal to the mole fraction of the solute

5 % Solution of cane sugar (m.wt. 342) is isotonic with 0.877 % solution of urea. What is the molecular weight of urea? *

2 points



30 u

120 u

60 u

180 u

What is the normality of 2.5 M sulphuric acid *

2 points



5.0 N

10.0 N

2.5 N

4.5 N

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Answers

Answered by sunitasharmasujal
1

Answer:

Here is your answer buddy

For a dilute solution, Raoult's law states that: The relative lowering of vapour pressure is equal to the mole fraction of solute. Here, Po is the pressure of pure solvent, P is the partial pressure of solution and XB is the mole fraction of solute.

According to Raoult's law, for dilute solutions containing non volatile solute, the relative lowering at vapour pressure is proportional to the mole of In consequence, the relative lowering of vapour pressure of a dilute solution of nonvolatile solute is equal to the mole fraction of solute.

According to Raoult's law, for dilute solutions containing non volatile solute, the relative lowering of vapor pressure, Δp/po is equal to the mole fraction of solute, X2. ... * The lowering of vapor pressure is proportional to the mole fraction of solute or inversely related to mole fraction of solvent.

The effect of Raoult's Law is that the saturated vapor pressure of a solution is going to be lower than that of the pure solvent at any particular temperature. ... If you draw the saturated vapor pressure curve for a solution of a non-volatile solute in water, it will always be lower than the curve for the pure water.

Thanks....

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