Question

for dissociation of NH3 (taken in significant amount) occuring over small Pt surface, rate of dissociation of NH3 when it is taken at 20 bar pressure is 10⁻²bar/min. calculate rate of appearance of H₂ when NH₃ is taken at 30 bar pressure.

Answer 1

Answer:

31/27

Explanation:

NH₂COONH₄(s) = 2NH₃(g) + CO₂(g)

Step 1:

Let the initial partial pressure be “P”.  

So, according to the balanced equation given, the partial pressure of NH₃ is “2P” and CO₂ is “P” .

The initial/original total pressure becomes = 2P + P = 3P……. (i)

∴ Kp = [ρNH₃]² [ρCO₂]  

Or, Kp = [2P]² * [P] …….. (ii)

Step 2:

Since after adding NH₃, the partial pressure of NH₃ now becomes equal to the initial total partial pressure i.e., 3P and partial pressure of CO₂ will be “ P’ ”.

Total final pressure = 3P + P’ …… (iii)

∴ Kp = [3P]² * [P’] …….. (iv)

Step 3:

Equating (ii) & (iv), we get

[2P]² * [P] = [3P]² * [P’]

Or, 4 P = 9 P’

Or, P’ = 4P / 9 ….. (v)

Step 4:

Thus,

The ratio of the total final pressure to the initial/original total pressure  is

= [3P + P’] / 3P ...... [from (i) & (iii)]

= [3P + (4P/9)] / 3P ........ [from (v)]

= [27P + 4P] / 27P

= 31/27

Read more on Brainly.in - https://brainly.in/question/12126627#readmore

Explanation:

plz mark as brainliest