For each of the following figures, find the area of the shaded portion.
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we will use the formula for area= 1/2×base× height
Let the square be ABCD and parallelogram be PQRS then,
in ∆APD,
base = 3
height= 12
Area= 1/2×3×12
Area= 18
Area of shaded portion= area of ∆APD + area of ∆QCR
Area of Shaded Portion= 18+18 = 36
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