for each of the following ,find the quadratic polynomial whose sum and product respectively of the zeroes given .Also find the zeroes of these polynomials by factorisation. (1)-8/3,4/3
Answers
Sum of roots = -8/3 .
Product of roots = 4/3
Now,
We know that,
Quadratic equation =>
x² - ( sum of roots) x + product of roots = 0 .
x² - ( -8/3)x + 4/3 = 0 .
x² + 8/3x + 4/3 = 0
3x² + 8x + 4 = 0 .
By Factorisation :-
x² + 2/3x + 2x + 4/3 = 0
x ( x + 2/3 ) + 2 ( x + 2/3 ) = 0
( x + 2 ) ( x + 2/3 ) = 0
x = -2 or -2/3
By Formula :-
Now, x = -8±√8²-4(3)(4) / 2(3)
x = -8 ± √ 64 - 48 / 6 = -8 ± √16 / 6 = -8 ± 4 / 6
x = -8 + 4 / 6 or -8 -4 /6
x = -2/3 , -2 .
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Sum of roots = 21/8
Product of roots = 5/16
Now,
We know that,
Quadratic equation =>
x² - ( sum of roots) x + product of roots = 0 .
x² - ( 21/8)x + 5/16 = 0 .
16x² - 42x + 5 = 0 .
By Factorisation :
16x² - 42x + 5 = 0
16x² - 2x -40x + 5 = 0
2x ( 8x - 1 ) -5 ( 8x -1 ) = 0
2x - 5 ( 8x - 1 ) = 0
x = 5/2 or 1/8
By Formula :-
x = -(-42)± √ (42²) - 4(16)(5) / 2 (16 )
x = 42 ± √ 1764 - 320 / 32
x = 42 ± √ 1444 / 32
x = 42 ± 38 / 32
x = 80/32 or 4/32
x = 20 / 8 or 1/8
x = 5/2 or 1/8
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Answer:
Step-by-step explanation:
Sum of roots = -8/3 .
Product of roots = 4/3
Now,
We know that,
Quadratic equation =>
x² - ( sum of roots) x + product of roots = 0 .
x² - ( -8/3)x + 4/3 = 0 .
x² + 8/3x + 4/3 = 0
3x² + 8x + 4 = 0 .
By Factorisation :-
x² + 2/3x + 2x + 4/3 = 0
x ( x + 2/3 ) + 2 ( x + 2/3 ) = 0
( x + 2 ) ( x + 2/3 ) = 0
x = -2 or -2/3
By Formula :-
Now, x = -8±√8²-4(3)(4) / 2(3)
x = -8 ± √ 64 - 48 / 6 = -8 ± √16 / 6 = -8 ± 4 / 6
x = -8 + 4 / 6 or -8 -4 /6
x = -2/3 , -2 .