For each sequence, find the first 4 terms and the 10th form
a) n²+3
b)2n²
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Answer:
Given that: Tn=n+1n2
Then T1=1+112=21,T2=2+122=34,T3=3+132=49,T4=4+142=516
∴ The first four terms of the sequence are 21,34,49,516.
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