Question

For equation x = t^2 - 4t+ 10 displacement of
particle till it come to rest from starting will be
(1) 20 m
(2) -10 m
« (3) 4 m
(4) 10 m​

Answer 1

Answer:

(c) 4 m

Explanation:

Given the displacement in the equation form as

$x=t^{2} -4t+10$

Particle comes to rest means the velocity of the particle is zero. This gives

$\frac{dx}{dt} = 2t-4=0$

Or $t=2 s$

Means the particle comes to rest after 2 second.

The position of particle at t=0 is

$x_{t=0}=10$

The position of particle after `coming to rest ( t=2 s ),

$x_{t=2} =4-8+10=6$

The displacement will be $x_{t=0} -x_{t=2} =10-6=4 m$