Question

For every natural number ‘n’, 6n always ends with the digit

a. 4

b. 8

c. 6

d. 0

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Answer 1

I think " 0 " ------------------

Answer 2

Answer:

$first\ let\ us\ try\ using\ 6^2, \\6^2 = 36, \\now, 6^3,\\ 6^3 = 216$

as we can see here, no matter what natural number 'n', $6^n$ will always end with 6.

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