for every positive integer n,prove that 7n- 3n is divisible by 4
Answers
Answer:
for every positive integer n, 7n- 3n is divisible by 4
Step-by-step explanation:
For every positive integer n,prove that 7n- 3n is divisible by 4
Let assume than n is a positive integer
7n - 3n
= 4n
= 4 * n
=> (7n - 3n)/4 = 4n/4
=> (7n - 3n)/4 = n
While n a positive integer as it was assumed
Hence (7n - 3n) is divisible by 4 as it is resulting in an integer
Hence we can say that for every positive integer n, 7n- 3n is divisible by 4
Answer:
Step-by-step explanation:
Let n be a positive number from the set of natural numbers.
Since n will be always on the positive side of the number line.
We have now equation f(n)= 7*n - 3*n.
Here value of n is from a natural number set and it remains constant in the function. Hence we can also simplify that function to n(7-3) = 4*n.
Now 4*n being a multiple of 2 is an even number. Hence it is also evident that 4*n is clearly divisible by 4.
We take an example as n=1 and n=2
When n=1, we have in function value of n=1, then 7n-3n comes out to be 7-3=4 which is clearly divisible by 4.
When n=2, we have value of n as 2, and the equation comes out to be 14-6 = 8 which is clearly divisible by 4.