For first order reaction a gives products the rate of reaction at a equals to 0.2 mole is 1 into 10 to the power minus 2 mole per litre per minute The Half Life Period of the reaction is
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Let us considwer the problem:-
r=[A]
Implies that
k=
0.2
10
−2
=5.0×10
−2
Therefore
t
2
1
=
K
0.693
Putting value of k in above equation, we have
t
2
1
=
5.0×10
−2
0.693
=13.86 min
Hance,
=832 sec
December 26, 2019
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