For how long should a force of 400N act on a body of mass 20kg so that it acquires a velocity of 180 m+s
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Force can be written as a product of mass and acceleration.
i.e Force= mass x acceleration
F= ma
acceleration = Δvelocity/time (i.e initial velocity - final velocity ÷ time taken)
a = (v-u)/t v= 180m/s u= 0m/s(body was not moving) t is time taken.
Therefore F can be given by m x (v-u)/t
F= m(v-u)/t
400N= 20(180-0)/t
400= 3600/t ......cross multiply
400t= 3600 ...divide both sides by 400 to find t
t= 3600/400 t = 9s
There time required is 9 seconds
i.e Force= mass x acceleration
F= ma
acceleration = Δvelocity/time (i.e initial velocity - final velocity ÷ time taken)
a = (v-u)/t v= 180m/s u= 0m/s(body was not moving) t is time taken.
Therefore F can be given by m x (v-u)/t
F= m(v-u)/t
400N= 20(180-0)/t
400= 3600/t ......cross multiply
400t= 3600 ...divide both sides by 400 to find t
t= 3600/400 t = 9s
There time required is 9 seconds
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