For how long should a force of 50 N act on a body of 5 kg so that it acquires a velocity of 100 m/ s?
Answers
Answer:
Step-by-step explanation:
- Force (F) = 50 N
- Mass (m) = 5 kg
- Initial velocity (u) = 0 m/s
- Final velocity (v) = 100 m/s
- Time (t)
→ By Newton's second law of motion,
F = m (v - u)/t
→ Substituting the given datas, we get
50 = 5 (100 - 0)/t
t = 500/50
→ Newton's second law state that the rate of change of momentum is directly proportional to the force applied and the change takes place in the direction of the force.
→ The unit of force is Newton in SI system and dyne in CGS system.
Given :–
- Force (F) = 50N
- Mass (m) = 5kg
- Initial velocity (u) = 0
- Final Velocity (v) = 100m/s
To Find :–
- Time for which the force is applied.
Solution :–
First, we need to find the acceleration,
So, for finding the value of acceleration,
We know that,
⟹ F = ma
So,
here we need to find the acceleration,
⟹ a =
- F = 50
- m = 5
⟹ a =
- Cut the denominator (5) and the numerator (50), we obtain
⟹ a = 10
- a = 10m/s²
Now, time for which force is applied,
⟹
Here, we have
- v = 100m/s
- u = 0
- a = 10m/s²
⟹
Cancel the denominator (0) and the numerator (0) and also denominator (m/s) is cancel by the numerator (m/s) but second is in the form of s² So, s is remains same.
⟹
It means,
⟹ 10s
Hence,
Time of which the force is applied in 10s