Math, asked by ishikarathi443, 10 months ago

For how long should a force of 50 N act on a body of 5 kg so that it acquires a velocity of 100 m/ s?

Answers

Answered by TheValkyrie
6

Answer:

\bigstar{\bold{Time\:=\:10\:s}}

Step-by-step explanation:

\Large{\underline{\underline{\it{Given:}}}}

  • Force (F) = 50 N
  • Mass (m) = 5 kg
  • Initial velocity (u) = 0 m/s
  • Final velocity (v) = 100 m/s

\Large{\underline{\underline{\it{To\:Find:}}}}

  • Time (t)

\Large{\underline{\underline{\it{Solution:}}}}

→ By Newton's second law of motion,

  F = m (v - u)/t

→ Substituting the given datas, we get

 50 = 5 (100 - 0)/t

 t = 500/50

 \boxed{\bold{Time\:=\:10\:s}}

\Large{\underline{\underline{\it{Notes:}}}}

→ Newton's second law state that the rate of change of momentum is directly proportional to the force applied and the change takes place in the direction of the force.

→ The unit of force is Newton in SI system and dyne in CGS system.

Answered by Uriyella
5

Given :–

  • Force (F) = 50N
  • Mass (m) = 5kg
  • Initial velocity (u) = 0
  • Final Velocity (v) = 100m/s

To Find :–

  • Time for which the force is applied.

Solution :–

First, we need to find the acceleration,

So, for finding the value of acceleration,

We know that,

⟹ F = ma

So,

here we need to find the acceleration,

⟹ a =  \dfrac{F}{m}

  • F = 50
  • m = 5

⟹ a =  \dfrac{\cancel{50}}{\cancel{5}}

  • Cut the denominator (5) and the numerator (50), we obtain

⟹ a = 10

  • a = 10m/s²

Now, time for which force is applied,

 \dfrac{v - u}{a}

Here, we have

  • v = 100m/s
  • u = 0
  • a = 10m/s²

 \dfrac{10 \cancel{0} - 0 \: m/s}{1 \cancel{0} \: {m/s}^{2}}

Cancel the denominator (0) and the numerator (0) and also denominator (m/s) is cancel by the numerator (m/s) but second is in the form of s² So, s is remains same.

 \dfrac{10}{1} s

It means,

⟹ 10s

Hence,

Time of which the force is applied in 10s

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